Equilibrium Lab(全英文)

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    Object;
    Part A - Determine the changing color of the indicator(nethyl orange) in the
           reaction(HCL + NaOH) and with water..
    Part B - Determine the reaction to form Iron Thiocyanate.

    Discussion;

    Part A – Q.1  addition of acid --- NaOH + HCL ⇔ NaCl + H2O (orange color)
    Part A – Q.2  addition of acid --- NaCl + H2O ⇔ NaOH + HCL (reddish color)
    Part A – Q.2  Changing color
    Part A – Q.3  addition of acid --- reaction shift right
    Part A – Q.2  addition of base --- reaction shift left
    Part A – Q.4  When we added base to acid, color became light orange. And when we added acid to
    Part A – Q.4  base, color turned reddish color.

    Part B – Q.1  FeCl3 + KSCN ⇔ FeSCN + KCl3  (darkred)
    Part A – Q.2  There were no changes.
    Part A – Q.3  There were no changes.
    Part A – Q.4  Became clear. (orange, darkred precipitate)
    Part A – Q.5  FeCl3 + NaOH → Fe(OH) 3 + NaCl3
    Part A – Q.6  Became clear. (whitish precipitate) AGSCN
    Part A – Q.7  FeSCN + AgNO3 → AgSCN + FeNO3
    Part A – Q.8  If a system at equilibrium, and if we change concentration, pressure or temperature,
    Part A Q.8    reaction shift to the direction which we changed concentration, pressure or
    Part A Q.8    temperature.

    資料の原本内容( この資料を購入すると、テキストデータがみえます。 )

    *Equilibrium Lab.
    /Object;
    Part A - Determine the changing color of the indicator(nethyl orange) in the
    reaction(HCL + NaOH) and with water..
    Part B - Determine the reaction to form Iron Thiocyanate.
    /Procedure;
    See attachment (handout).
    /Materials;
    Plate, water, 0.1mol HCL, 0.1mol NaOH, methyl orange, 0.1M FeCl3,,, 0.1M KSCN, 0.1M AgNO3,
    /Observations;
    > Part A. (Data table)
    + Methyl Orange (Color; orange) Water Became clear (light orange) +0.1M (1 drop) HCL Rose Pink (clear solution) +0...

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